Possible Data interpretation & probability Questions for RBI Assistant 2015
Since RBI Assistant exam is coming soon, so here is a Possible Data interpretation & probability Questions for RBI Assistant 2015. Solve this questions for practice
Working male and female population (in lakh) in various cities
1. What is the difference between the number of working females in Bangalore and the number of working males in Chennai?
A) 12.5 lakh
B) 11 lakh
C) 10 lakh
D) 12 lakh
E) 15 lakh
2. In which city is the income per working person the minimum?
A) Delhi
B) Jaipur
C) Bangalore
D) Chennai
E) Mumbai
3.What is the sum of the average working male and average working female population of the given six cities (calculate approximate value)?
A) 63.35 lakh
B) 53.75 lakh
C) 51.48 lakh
D) 49.96 lakh
E) 65.51 lakh
4.The number of working females in Mumbai is what percent of the number of working males in Bangalore?
A) 95%
B) 110%
C) 125%
D) 132%
E) None of these
For Question (5-7) A three-digit number is formed with the digits 1, 2, 3, 4, 5 at random.
5. What is probability that number formed is divisible by 2?
A) 29/60
B) 23/60
C) 2/5
D) 3/5
E) None of these
6. What is probability that number formed is not divisible by 2?
A) 21/60
B) 3/5
C) 2/5
D) 3/9
E) None of these.
7.What is probability that number formed is divisible by 5 ?
A) 1/5
B) 2/5
C) 3/5
D) 4/5
E) None of these
8. In a class, there are 15 boys and 10 girls. Three students are selected at random. The probability that 1 girl and 2 boys are selected, is
A) 10/13
B) 1/2
C) 21/46
D) 11/23
E) None of these.
9 .From a pack of 52 cards, two cards are drawn together at random. What is the probability of both the cards being kings?
A) 331/221
B) 13/221
C) 33/221
D) 1/221
E) None of these.
10. Two dice are tossed. The probability that the total score is a prime number is
A) 1/2
B) 5/12
C) 1/6
D) 7/9
E) None of these.
Answer & Explanation :
1. C
2. B
3. B
4. E
5. C
6. B
7. A
8. C
9. D
10. B
Hints For Ques. (5-10)
5. (C) From the given digits 1, 2, 3, 4, 5 numbers formed is n(S) = 5P3= 60
For divisibility with 2, even number or 0 should appear at unit place, here 2, 4 are even numbers and can occupy unit place in 2! ways, Rest 2 place can be filled in 4P2 ways
n(E) = 4P2*2 =12*2=24
Required Probability = 24/60 =2/5
6. (B)Probability that not divisible by 2 = 1- Probability that divisible by 2 =1-2/5 =3/5
7. (A) A number ends with 5, 0 then the number will be divisible by 5
Here only 5 is present, end place will be fixed by 5 so,
n(E)= 4P2
n(S)= 5P3
Required probability = 4P2/5P3= 1/5
8.(C) Required Probability = (10C1*15C2)/ 25C3 = 21/46
9. (D) Required probability =4C2/52C2 =1/221
10.(B) 15/36 =5/12
